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Edgar 2023-07-10 16:14:39 +02:00
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@ -134,7 +134,7 @@ It works by taking successive values of an arbitrary [quadratic polynomial](http
We will use `hash(key) + (i + i^2) / 2`.
Let `x` be the value of `hash(key) (mod capacity)`.
Let `x` be the value of `hash(key)`.
Starting with `i = 0`: