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Print logs only once even if fail is called multiple times

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ChillerDragon 2024-01-21 16:05:02 +08:00
parent de5a403a25
commit 8b74e2929d
1 changed files with 25 additions and 20 deletions
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45
integration_test/run.sh
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@ -124,24 +124,28 @@ trap cleanup EXIT
function fail() {
local msg="$1"
# the first tail get swalloed
# idk why so tail twice to ensure
# getting output
# this is a bit ugly but it works
# maybe a sleep does as well
# or I still did not get flushing
tail "$ruby_logfile" &>/dev/null
if [[ "$testname" =~ ^client/ ]]
if [ ! -f "$tmpdir/fail.txt" ]
then
echo "[-] end of ruby client log:"
tail "$ruby_logfile"
echo "[-] end of server log:"
tail "$logdir/server.txt"
else
echo "[-] end of ruby server log:"
tail "$ruby_logfile"
echo "[-] end of client log:"
tail "$logdir/client.txt"
touch "$tmpdir/fail.txt"
# the first tail get swalloed
# idk why so tail twice to ensure
# getting output
# this is a bit ugly but it works
# maybe a sleep does as well
# or I still did not get flushing
tail "$ruby_logfile" &>/dev/null
if [[ "$testname" =~ ^client/ ]]
then
echo "[-] end of ruby client log:"
tail "$ruby_logfile"
echo "[-] end of server log:"
tail "$logdir/server.txt"
else
echo "[-] end of ruby server log:"
tail "$ruby_logfile"
echo "[-] end of client log:"
tail "$logdir/client.txt"
fi
fi
echo "$msg"
exit 1
@ -151,14 +155,15 @@ function timeout() {
local seconds="$1"
sleep "$seconds"
echo "[-] Timeout -> killing: $testname"
touch timeout.txt
touch "$tmpdir/timeout.txt"
pkill -f "$testname killme"
kill_all_jobs
fail "[-] Timeout"
}
echo "[*] running test '$testname' ..."
[[ -f timeout.txt ]] && rm timeout.txt
[[ -f "$tmpdir/timeout.txt" ]] && rm "$tmpdir"/timeout.txt
[[ -f "$tmpdir/fail.txt" ]] && rm "$tmpdir"/fail.txt
if [[ "$testname" =~ ^client/ ]]
then
echo "ruby client log $(date)" > "$ruby_logfile"
@ -255,7 +260,7 @@ fi
echo "[*] waiting for jobs to finish ..."
wait
if [ -f timeout.txt ]
if [ -f "$tmpdir/timeout.txt" ]
then
echo "[-] Error timeouted"
exit 1